What is the GR precession per second?

[m***@wanadoo.fr]

[...]

The GR formula 6Pi * GM/(c^2*a(1-e^2)) gives the precession
in radians per revolution. Did you ever asked yourself
about the meaning of that "revolution"?
It is simply the KEPLERIAN revolution!

It is nothing of the sort, you boring little person. This is not
classical mechanics and the rules of Kepler do not apply.
Quit squabbling about a subject you don't understand.

Then calculate, using and *showing* the formulas, that
apply according to you, the GR precession of Mercury per century.

Marcel Luttgens

[m***@wanadoo.fr]

[...]

The GR formula 6Pi * GM/(c^2*a(1-e^2)) gives the precession
in radians per revolution. Did you ever asked yourself
about the meaning of that "revolution"?
It is simply the KEPLERIAN revolution!

It is nothing of the sort, you boring little person. This is not
classical mechanics and the rules of Kepler do not apply.
Quit squabbling about a subject you don't understand.

I wrote:

"The GR formula 6Pi * GM/(c^2*a(1-e^2)) gives the precession
in radians per revolution. Did you ever asked yourself
about the meaning of that "revolution"?

It is simply the KEPLERIAN revolution!"

You replied:

"It is nothing of the sort, you boring little person. This is not
classical mechanics and the rules of Kepler do not apply."

Take Mercury for instance.

6Pi * GM/(c^2*a(1-e^2)) = 0.1038 arc-seconds par revolution.
Multiply that value by the number of revolutions per century,
i.e. about 415, and you get a GR precession of about 43 seconds.
Calculate the number of revolutions of Mercury per century,
using the Kepler law. You should get about 415.
Now use the GR formula instead of the Kepler law (if you can!).
You should also get about 415 rev/century. How can you claim
that the rules of Kepler don't apply in this case?

Marcel Luttgens

[m***@wanadoo.fr]

Post by m***@wanadoo.fr

[...]

The GR formula 6Pi * GM/(c^2*a(1-e^2)) gives the precession
in radians per revolution. Did you ever asked yourself
about the meaning of that "revolution"?
It is simply the KEPLERIAN revolution!

It is nothing of the sort, you boring little person. This is not
classical mechanics and the rules of Kepler do not apply.
Quit squabbling about a subject you don't understand.

"The GR formula 6Pi * GM/(c^2*a(1-e^2)) gives the precession
in radians per revolution. Did you ever asked yourself
about the meaning of that "revolution"?
It is simply the KEPLERIAN revolution!"
"It is nothing of the sort, you boring little person. This is not
classical mechanics and the rules of Kepler do not apply."
Take Mercury for instance.
6Pi * GM/(c^2*a(1-e^2)) = 0.1038 arc-seconds par revolution.
Multiply that value by the number of revolutions per century,
i.e. about 415, and you get a GR precession of about 43 seconds.
Calculate the number of revolutions of Mercury per century,
using the Kepler law. You should get about 415.
Now use the GR formula instead of the Kepler law (if you can!).
You should also get about 415 rev/century. How can you claim
that the rules of Kepler don't apply in this case?
Marcel Luttgens- Hide quoted text -
- Show quoted text -

[m***@wanadoo.fr]

[...]

The GR formula 6Pi * GM/(c^2*a(1-e^2)) gives the precession
in radians per revolution. Did you ever asked yourself
about the meaning of that "revolution"?
It is simply the KEPLERIAN revolution!

It is nothing of the sort, you boring little person. This is not
classical mechanics and the rules of Kepler do not apply.
Quit squabbling about a subject you don't understand.

For Mercury, the GR formula 6Pi * GM/(c^2*a(1-e^2))
gives a precession of 0.1038 arc-seconds par revolution.
When one multiplies that value by the number of revolutions
per century, i.e. about 415, one gets a precession of
about 43 arc-seconds.

Which GR formula would you use to calculate that number?

Marcel Luttgens

[m***@wanadoo.fr]

Post by m***@wanadoo.fr

[...]

The GR formula 6Pi * GM/(c^2*a(1-e^2)) gives the precession
in radians per revolution. Did you ever asked yourself
about the meaning of that "revolution"?
It is simply the KEPLERIAN revolution!

It is nothing of the sort, you boring little person. This is not
classical mechanics and the rules of Kepler do not apply.
Quit squabbling about a subject you don't understand.

For Mercury, the GR formula 6Pi * GM/(c^2*a(1-e^2))
gives a precession of 0.1038 arc-seconds par revolution.
When one multiplies that value by the number of revolutions
per century, i.e. about 415, one gets a precession of
about 43 arc-seconds.
Which GR formula would you use to calculate that number?
Marcel Luttgens- Hide quoted text -
- Show quoted text -

[m***@wanadoo.fr]

Post by m***@wanadoo.fr

[...]

The GR formula 6Pi * GM/(c^2*a(1-e^2)) gives the precession
in radians per revolution. Did you ever asked yourself
about the meaning of that "revolution"?
It is simply the KEPLERIAN revolution!

It is nothing of the sort, you boring little person. This is not
classical mechanics and the rules of Kepler do not apply.
Quit squabbling about a subject you don't understand.

Then calculate, using and *showing* the formulas, that
apply according to you, the GR precession of Mercury per century.
Marcel Luttgens- Hide quoted text -
- Show quoted text -

[m***@wanadoo.fr]

[...]

The GR formula 6Pi * GM/(c^2*a(1-e^2)) gives the precession
in radians per revolution. Did you ever asked yourself
about the meaning of that "revolution"?
It is simply the KEPLERIAN revolution!

It is nothing of the sort, you boring little person. This is not
classical mechanics and the rules of Kepler do not apply.
Quit squabbling about a subject you don't understand.

Moron,

For Mercury, the GR formula 6Pi * GM/(c^2*a(1-e^2))
gives a precession of 0.1038 arc-seconds par revolution.
When one multiplies that value by the number of revolutions
per century, i.e. about 415, one gets a precession of
about 43 arc-seconds.

Which GR formula would you use to calculate that number?

Marcel Luttgens

[m***@wanadoo.fr]

[...]

The GR formula 6Pi * GM/(c^2*a(1-e^2)) gives the precession
in radians per revolution. Did you ever asked yourself
about the meaning of that "revolution"?
It is simply the KEPLERIAN revolution!

It is nothing of the sort, you boring little person. This is not
classical mechanics and the rules of Kepler do not apply.
Quit squabbling about a subject you don't understand.

Moron,

For Mercury, the GR formula 6Pi * GM/(c^2*a(1-e^2))
gives a precession of 0.1038 arc-seconds par revolution.
When one multiplies that value by the number of revolutions
per century, i.e. about 415, one gets a precession of
about 43 arc-seconds.

Which GR formula would you use to calculate that number?

Marcel Luttgens