Discussion:
Conservation of angular momentum
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Peter
2007-05-29 16:39:49 UTC
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As I understand it, Lagrange and Hamilton did not invent new physics;
everything they said can be derived from Newton's laws of motion. But
I see an incompatibility between torque r x F and Newton's second law
F = dp.dt. In Newton's equation, there is no room for an r.
F = dp/dt p is linearmomentum
T = dL/dt L isangularmomentum
I know that. The problem I have is that separateconservationlaws for
linear andangularmomentumconflict with reality.
No, the reality is that there are separateconservationlaws.
I saw a device
(which I understand will soon be on the market), consisting of a
closed air track, with roughly the shape of a horseracing track,
where it is clearly seen linear andangularmomentumreadily convert
into each other. This conflicts with two separateconservationlaws.
No, we've been over this ground before. You posted the same
thing previously and your claims were refuted then. Nothing
has changed in the interim.- Hide quoted text -
- Show quoted text -
Do you mean that what I saw was a mirage? Besides, what about the
collision between a point object of mass m and an equal-arm lever of
mass 6m. Calculation using r x p shows it is impossible for both
angularmomentumand kinetic energy to be transferred, even under
ideal conditions. Nobody offered a satisfactory explanation.
For people suffering from your condition, nobody ever will.
Isn't that fantastic?
Dirk Vdm- Hide quoted text -
- Show quoted text -
Are you dodging the question?
You are dodging the answers.
You always have and you always will.
Isn't that brilliant?
Dirk Vdm- Hide quoted text -
- Show quoted text -
No, that would be dumb. You are the brilliant one, evading answering.

Peter
Peter
2007-05-29 16:48:30 UTC
Permalink
As I understand it, Lagrange and Hamilton did not invent new physics;
everything they said can be derived from Newton's laws of motion. But
I see an incompatibility between torque r x F and Newton's second law
F = dp.dt. In Newton's equation, there is no room for an r.
F = dp/dt p is linearmomentum
T = dL/dt L isangularmomentum
I know that. The problem I have is that separateconservationlaws for
linear andangularmomentumconflict with reality.
No, the reality is that there are separateconservationlaws.
I saw a device
(which I understand will soon be on the market), consisting of a
closed air track, with roughly the shape of a horseracing track,
where it is clearly seen linear andangularmomentumreadily convert
into each other. This conflicts with two separateconservationlaws.
No, we've been over this ground before. You posted the same
thing previously and your claims were refuted then. Nothing
has changed in the interim.- Hide quoted text -
- Show quoted text -
Do you mean that what I saw was a mirage? Besides, what about the
collision between a point object of mass m and an equal-arm lever of
mass 6m. Calculation using r x p shows it is impossible for both
angularmomentumand kinetic energy to be transferred, even under
ideal conditions. Nobody offered a satisfactory explanation.
For people suffering from your condition, nobody ever will.
Isn't that fantastic?
Dirk Vdm- Hide quoted text -
- Show quoted text -
Are you dodging the question?
You are dodging the answers.
You always have and you always will.
Isn't that brilliant?
Dirk Vdm- Hide quoted text -
- Show quoted text -
No, that would be dumb. You are the brilliant one, evading answering.

Peter

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