On Feb 22, 2:23 pm, Eric Gisse <***@gmail.com> wrote:
Dear Eric, Dunce 3: All objects being acted upon by gravity are
experiencing the mass-proportional force of gravity caused by the
ether that is constantly flowing through the mass. That means that
all falling objects have an intrinsic beginning KE equal to the
object's static weight. Momentum is: The increase in hitting power
(expressed in pounds, only) caused by having the object increase in
velocity in increments of the datum velocity of 32/174 feet per
second. The formula is: F = v/32.174 (m). Kinetic energy is a close
cousin of momentum and is: The increase in hitting power (expressed
in pounds) of an accelerating object being acted upon be a single
value uniform force in a single direction, and increases in increments
of the datum "acceleration" of 32.174 feet per second EACH second.
Additionally, because there is a continuous force causing the
acceleration, that force must be added to the calculated hitting power
of the accelerating object. The correct formula is: KE = a/g (m) + v/
32.174 (m). — NoEinstein —
Dear Eric: Your link to the 'Physics 101 Lab Manual' has no
experiment that confirms KE = 1/2mv^2.
Other than Lab #4 and #5 which do, of course.
At no point have I disagreed
with Newton's three laws of motion! I've just said that F = ma (Law
2) produces no useful data.
If you think so, the results of Lab #1 will amaze you.
The only equation needed to solve most problems in dynamics is my own,
KE = a/g (m) + v/32.174 (m).
A fascinating assertion since you are yet to solve any mechanics
problem with that equation.
Eric: That absolutely correct equation predicted the height of fall
needed to cause a small clevis pin to have a KE matching a larger
clevis pin. When that happens, the two pins stay in compressed
contact long enough to dampen the ringing tone of the smaller pin
(clunk, not 'ping'). The Coriolis equation, KE = 1/2 mv^2 greatly
underestimated the first second KE, because it didn't consider that
all falling objects begin (at time ZERO) with a KE matcing the
object's static weight. After about 2.7 seconds of fall, Coriolis's
equation greatly exaggerates the KE by having such be semi-parabolic,
when in actuality, KE increases exactly one weight unit per SECOND of
free-fall. Is the latter too complicated for you to understand,
Eric? Ha, ha, HA! — NoEinstein —
Weight is not kinetic energy. Why am I wasting my time talking to you?
You are clueless with nothing to offer. I think its' time to return
you to responding to yourself over and over because nobody else cares.
[...]
Dear Eric, Dunce 3: All objects being acted upon by gravity are
experiencing the mass-proportional force of gravity caused by the
ether that is constantly flowing through the mass. That means that
all falling objects have an intrinsic beginning KE equal to the
object's static weight. Momentum is: The increase in hitting power
(expressed in pounds, only) caused by having the object increase in
velocity in increments of the datum velocity of 32/174 feet per
second. The formula is: F = v/32.174 (m). Kinetic energy is a close
cousin of momentum and is: The increase in hitting power (expressed
in pounds) of an accelerating object being acted upon be a single
value uniform force in a single direction, and increases in increments
of the datum "acceleration" of 32.174 feet per second EACH second.
Additionally, because there is a continuous force causing the
acceleration, that force must be added to the calculated hitting power
of the accelerating object. The correct formula is: KE = a/g (m) + v/
32.174 (m). — NoEinstein —