Richard Tobin
2010-11-24 15:54:31 UTC
| >xi = (x-vt)/sqrt(1 - v^2/c^2) -- Einstein.
| You have misread the paper. Xi is not the length of the moving rod
| measured in the stationary system. It is the coordinate in the
| moving system corresponding to x in the stationary one.
You haven't read the paper.
Wrong.| You have misread the paper. Xi is not the length of the moving rod
| measured in the stationary system. It is the coordinate in the
| moving system corresponding to x in the stationary one.
You haven't read the paper.
"We now inquire as to the length of the moving rod" -- Einstein
What IS the length of the moving rod, genius?
If the rod lies between xi = 0 and xi = L in the moving system at timeWhat IS the length of the moving rod, genius?
t = 0 then - using the formula you quote above - it will lie between
x = 0 and x = L sqrt(1-v^2/c^2) in the stationary system, so its
length will be L sqrt(1-v^2/c^2).
-- Richard