Discussion:
What is so bad about Relativity?
(too old to reply)
Richard Tobin
2010-11-24 15:54:31 UTC
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| >xi = (x-vt)/sqrt(1 - v^2/c^2) -- Einstein.
| You have misread the paper. Xi is not the length of the moving rod
| measured in the stationary system. It is the coordinate in the
| moving system corresponding to x in the stationary one.
You haven't read the paper.
Wrong.
"We now inquire as to the length of the moving rod" -- Einstein
What IS the length of the moving rod, genius?
If the rod lies between xi = 0 and xi = L in the moving system at time
t = 0 then - using the formula you quote above - it will lie between
x = 0 and x = L sqrt(1-v^2/c^2) in the stationary system, so its
length will be L sqrt(1-v^2/c^2).

-- Richard
spudnik
2010-11-25 03:45:00 UTC
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hopefully, the Burg Caliphate also has a big, subterranean garage; so,
when are you going to do this experiment?
<http://physics.nist.gov/cgi-bin/cuu/Value?c>
Either way, NIST are useless yankee wankers and WRONG.
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