rbwinn
2011-01-10 03:25:41 UTC
?"rotchm" wrote in message
news:be93af77-b522-4668-b735-
n' = t(1-v/c)
and if we define variable n, where n = t, as the time showing on a clock at
rest in S, we get
n' = n(1-v/c)
That equations doesn't give us the same speed of light in all frames
The means that a clock travelling in one direction, at a given speed, ticks
differently to a clock moving at the *same* speed in the opposite direction.
If you define the +x direction meaning to your right, then according to RB
you can change the ticking rate of a moving clock by simply turning around.
It is utter nonsense, as has been pointed out to him multiple times over
many years
Well, here is the thing, Inertial. We have a thing out here in thenews:be93af77-b522-4668-b735-
Yup, just as described by Poincare. Either you use SR algebra to
readily get what a clock predicts or you use Gal.Trans.eqs + Convert
(~LEt) to get what a clock predicts. Both approaches will give the
same result(s).
Of course, RB doesn't use Lorentz Transforms. He usesreadily get what a clock predicts or you use Gal.Trans.eqs + Convert
(~LEt) to get what a clock predicts. Both approaches will give the
same result(s).
n' = t(1-v/c)
and if we define variable n, where n = t, as the time showing on a clock at
rest in S, we get
n' = n(1-v/c)
That equations doesn't give us the same speed of light in all frames
The means that a clock travelling in one direction, at a given speed, ticks
differently to a clock moving at the *same* speed in the opposite direction.
If you define the +x direction meaning to your right, then according to RB
you can change the ticking rate of a moving clock by simply turning around.
It is utter nonsense, as has been pointed out to him multiple times over
many years
world called reality.
for reality. Why does a welder keep babbling about this stuff?
[...]
clock in S and a slow clock in S', how do both clocks get the same
speed for one frame of reference relative to the other?
t=(t'+vx'/c^2)/sqrt(1-v^2/c^2)
I guess maybe you did not know about these two equations.
frames will disagree on the velocity of an object in another frame.
Is there a particular reason you are unable to work out x/t (or dx/dt
if you actually know calculus) to answer your own question? One would
think you'd understand the trivial aspects of the theory since you've
been arguing about it since 1994 or so.
Well, I have a high school education which includes a little
calculus. I am talking to people with college degrees and Phd's in
physics [...]
smarter than you. Back to ignoring you, persistent idiot.