Discussion:
What is your EM crankosity?
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Don Kelly
2009-09-24 23:02:46 UTC
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If you can find a diagram that "illustrates" a TEM wave, you'll note that
the two waves are "mechanically" at 90 degrees, but they are in temporal
phase.
Really?
Loading Image...
If both E and M are zero at the same instant, energy is not conserved.
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Cute little diagram- too bad it doesn't illustrate anything related to the
analysis of such a wave.
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Don Kelly
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Eat shit, 10,000,000 flies can't be wrong.
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Don Kelly
2009-09-26 03:40:25 UTC
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"Androcles" <***@Hogwarts.physics_o> wrote in message news:02Xum.218924$e%***@newsfe13.ams2...
of Nature?
The one that adheres to the first law of thermodynamics and
Faraday's equation E = -dB/dt has the higher credibility.
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1) Faraday's law isn't as you indicated but relates the emf induced in a
closed path to the total flux enclosed and normal to the path which is the
same as one of Maxwell's equations expressed in the integral form.

2)The TEM wave situation is not equivalent to such a closed path.

3) The development of the E and B fields of such a wave is present in every
EM text and definitely shows that tehe E and H components are in time phase.
just as the usual diagram (labelled and without coloured teardrops)
indicates.

4)PoyntingsTheorem shows that for E and H in time quadrature, the average
power and energy (per cycle) transmitted in the wave is 0. Only the "in
phase" component transmits power. If E and H were in time quadrature, we
wouldn't have radio, etc because we wouldn't be able to transmit any net
energy.

Take some time with a good text. Possibly you should start with the
situation in a simple electric circuit where v=Vme^jwt and i=Ime^jwt+a
evaluate the instantaneaous power vi and then evaluate the energy per
cycle for a =0, 90 degrees or whatever. At what a is the average energy the
greatest? At what a is it 0?
This isn't a TEM wave but the results do point the way and do use the trig
functions and Euler's theorem that you refer to- then draw a conclusion with
respect to E and H in the TEM wave.
http://en.wikipedia.org/wiki/Trigonometric_functions
http://en.wikipedia.org/wiki/Euler's_formula
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Don Kelly
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Don Kelly
2009-09-27 01:51:09 UTC
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"Androcles" <***@Hogwarts.physics_o> wrote in message news:02Xum.218924$e%***@newsfe13.ams2...
-----snip----------------
of Nature?
The one that adheres to the first law of thermodynamics and
Faraday's equation E = -dB/dt has the higher credibility.
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1) Faraday's law isn't as you indicated but relates the emf induced in a
closed path to the total flux enclosed and normal to the path which is the
same as one of Maxwell's equations expressed in the integral form. In the
point form it is "curl E" =-dB/dt.
What is not credible is your misapplication of concepts.

2)The TEM wave situation is not equivalent to such a closed path.

3) The development of the E and B fields for sinusoids (as indicated by the
use of Euler's e^jwt ...) in any EM text definitely shows that the E and H
components in free space are in time phase and E/H =root(muo/epso) is real.
This is represented by the usual diagram (labelled clearly and without the
multicolour balloons) in such texts.
Wiki has this part right.

4)PoyntingsTheorem shows that for E and H in time quadrature, the average
power and energy (per cycle) transmitted in the wave is 0. Only the "in
phase" component transmits power. If E and H were in time quadrature, we
wouldn't have radio, etc because we wouldn't be able to transmit any net
energy. And, yes, conservation of energy is not violated (how you got this
is a puzzlement).

Take some time with a good text. Possibly you should start with the
situation in a simple electric circuit where v=Vme^jwt and i=Ime^jwt+a and
then
evaluate the instantaneous power vi and then evaluate the energy per
cycle for a =0, 90 degrees or whatever. At what angle a is the average
energy the
greatest? At what a is it 0?

This isn't a TEM wave but the results are the related except for scalar
bugger factors, to the E cross H relationship where E and H are in space
quadrature. Use the trig functions and Euler's theorem that you refer to-
Then you can draw a conclusion for the TEM wave from analogy if you do not
care to actuall review the relationship between E and H in any EM text.

Sorry, I inadvertently sent this to your other group- alt.morons. I
apologise
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Don Kelly
***@shawcross.ca
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