Calculating the planks constant

[Paulo]

I understant that the plank constante is ususally consodered as a
fundamental physical constant thet cannot be calculated, but physics
is still changing and this seams interesting.
Supose an electron falls in an atom. The potential energy of the
electron is converted to cinetic energy, and i will assume this will
be rotation around the atoms nucleos. The spining electron will
radiate and dissipate its energy, and emitte a foton (after some point
the electron the radiated energy will equal the absorved energy and
the radiation will stop). The frequency of the foton will be given by
E = 1/2 m v^2 f = v / (2 pi r) E = 1/(4 pi epsilon) q^2 / r (coloumb
potential energy)
Resulting in
E = m^(1/2) q^(4/3) / (2 epsilon^(2/3) ) f^(2/3)
This means that E is proportional to f^(2/3), but for visible ligth
(f=10^15 Hz) one has,
E/f (f=10^15) = 9.8548E-34
h=E/f = 6.62607e-34
The result is more or less acurate! Any comments?
Paulo Lopes

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it gives the same eponent e-34. This is a 1 minute calculation. Maybe
with many simplifications, but i wonder if maybe it means something.
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   http://www.merriam-webster.com/dictionary/minute
Do you mean "minute" as a unit of time, as a distance, or as a steak?
I could calculate a minute steak right now... yummy.
Anyway, I'll save you the trouble of adding
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to what I write by doing it for you.
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Ok, ok, it took more than a minute. lol

[BURT]

Set H-bar to one.

Mitch Raemsch

[Paulo]

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I can't follow your link.

[Paulo]

In fact you can even say it only comes from the first since, the
second comes from the uncertatnty principles, when you try to use a
photon to measure the position and velocity at the same time (momento
and position) you will find that if you find the momento you can't
know the position.
From the equation for a movento, you know the wavelength and so the
particle is as sinusoid and has not defined position.

Paulo A. C. Lopes

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